5v^2+34-48=0

Solution for 5v^2+34-48=0 equation:

5v^2+34-48=0

We add all the numbers together, and all the variables

5v^2-14=0

a = 5; b = 0; c = -14;
Δ = b2-4ac
Δ = 02-4·5·(-14)
Δ = 280
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{280}=\sqrt{4*70}=\sqrt{4}*\sqrt{70}=2\sqrt{70}$
$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-2\sqrt{70}}{2*5}=\frac{0-2\sqrt{70}}{10}
=-\frac{2\sqrt{70}}{10}
=-\frac{\sqrt{70}}{5}
$
$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+2\sqrt{70}}{2*5}=\frac{0+2\sqrt{70}}{10}
=\frac{2\sqrt{70}}{10}
=\frac{\sqrt{70}}{5}
$